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Showing a side panel under certain conditions
Wanabo
Top  #1 Print Post
Posted on 21-02-2011 15:15
Trying to code a side panel that only appears if a certain condition is met (viewforum.php?forum_id=9). But I seem to be stuck. :(

Code Download source  

if (FUSION_SELF."?forum_id=9" == "viewforum.php?forum_id=9") {

openside("test");

echo THEME_BULLET." test
";

closeside();

}


It works fine when only FUSION_SELF and viewforum.php is used. I guess the problem is the questionmark and afterwards.
Cool
 
Ankur
Top  #2 Print Post
Posted on 22-02-2011 13:15
Have you tried $_GET['forum_id'] or something like that ?
Be What you want to be...Wink
 
www.php-fusion.in
Wanabo
Top  #3 Print Post
Posted on 25-02-2011 08:47
Yes but can't get it to work.

But I will try another way. Not comparing part of urls but reading the title tags or forum category name to match a keyword that triggers the panel to display.

My experiments in this direction where not successful.
Cool
 
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